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首页 (人教版)高一物理必修2第五章曲线运动测试题((person teach…

(人教版)高一物理必修2第五章曲线运动测试题((person teaches Edition) high one physics, compulsory 2, fifth chapter curve movement test question).doc

(人教版)高一物理必修2第五章曲线运动测试题(…

于夏来了
2017-10-20 0人阅读 举报 0 0 0 暂无简介

简介:本文档为《(人教版)高一物理必修2第五章曲线运动测试题((person teaches Edition) high one physics, compulsory 2, fifth chapter curve movement test question)doc》,可适用于IT/计算机领域

(人教版)高一物理必修第五章曲线运动测试题((personteachesEdition)highonephysics,compulsory,fifthchaptercurvemovementtestquestion)(人教版)高一物理必修第五章曲线运动测试题((personteachesEdition)highonephysics,compulsory,fifthchaptercurvemovementtestquestion)Xi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter,Xi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter(((people'sEducationEdition)PEPEditionPEPEdition)))HighschoolphysicsrequiredHighphysics,highrequirement,physicsrequiredSeniorphysicsrequiredTwentytwo,fifthchaptersThefifthchapterandthefifthchapterThefifthchaptercurvemotiontestCurvemotiontestcurvemotiontestCurvilinearmotiontestQuestionstopicFirst,fillintheblanks(indefinitechoice),aboutthesynthesisanddecompositionofmotion,thefollowingstatementiscorrectAhispeedisequaltothesizeofthesizeandspeedofmovementThetwomovementifthelinearmotionofBobjects,itsmotionmustbelinearmotionCmotionandmotionwithtimeIfthemotionisDcurvemovement,ismovingatleastonemotioncurveOneElevenOneAnalyticAnalyticsolutionAnalysis:::Thatisduetothespeedvector,synthesisanddecompositionaccordingtotheparallelogramrule,AerrorislinearmotionOptionsMotionorcurvilinearmotionisrelatedtothenatureofthemotionofthetwopoints,ifthemotionofthetwopointsisproportionaltotheaccelerationofthetwomotionThespeedisnotinastraightline,theobjectmotionismotioncurve,optionBandDerrorMotionandmotionItisthebasicnatureofisochronicity,motionsynthesisanddecomposition,theoptionCiscorrectanswer:Ctieasmallballwithathread,andpulltheotherendwiththehandsothattheballcanmoveataconstantspeedinthehorizontalplaneThelengthoftheropeisL,Thespeedoftheballishunger,ifthelengthoftheropeisshortenedtoL,thespeedoftheballbecomesV,andthecentripetalforceoftheballisoriginalComeAtimes,Btimes,Ctimes,DtimesTwoTwentytwoTwoAnalyticAnalyticsolutionAnalysis:accordingtotheformulaofcentripetalforce,thereisF=mVL,F=m(V)L=mvLObviously,F=F,theoptionDiscorrectforflatthrowmotion(regardlessofairresistance,Gisknown),thefollowingconditionscandeterminetheinitialvelocityoftheobjectis()AknownhorizontaldisplacementBknowndropheightCknowthemagnitudeanddirectionofthelandingvelocity,themagnitudeanddirectionoftheknowndisplacementoftheDThreeThirtythreeThreeAnalyticAnalyticsolutionAnalysis:::Thehorizontalmotionofhorizontalthrowingmotionisuniformlinearmotion,thatis,atanytime,VX=VknowsthespeedandsquareatanytimeT=gcanbedividedintoVXaccordingtospeed,andthesizeanddirectionofdisplacementcanbecalculatedbySXandHHseektime,InitialspeediscalculatedbyVx=sxtanswer:CDbecauseofthefrictionalresistanceofthespacecraftbytherarefiedairontheorbit,theorbitalheightwillgraduallydecrease,inwhichcasethespacecraftmovesEnergy,gravity,potentialenergy,andmechanicalenergychangewillbeAkineticenergy,gravity,potentialenergy,andmechanicalenergyalldecreasegraduallyThegravitationalpotentialenergyofBdecreasesgradually,thekineticenergyincreasesgradually,andthemechanicalenergyremainsunchangedThegravitationalpotentialenergyofCincreasesgradually,thekineticenergydecreasesgradually,andthemechanicalenergyremainsunchangedThegravitationalpotentialenergyofDdecreasesgradually,thekineticenergyincreasesgradually,andthemechanicalenergydecreasesgraduallyFourFortyfourFourAnalyticAnalyticsolutionBecausetheresistanceisverysmall,theorbitheightchangesveryslowly,andeachcircleofthesatellitecanstillbeconsideredasuniform,roundandroundDynamicThemechanicalenergyofthesatelliteisreducedaccordingtothemechanicalenergytheorembecauseofthenegativeworkdonebythefrictionalresistanceTheenergypotentialofthesatellitedecreases,byROneRGMV=thesatellitekineticenergywillincreaseItalsoillustratestheprocessTheworkisgreaterthanthegravitytoovercometheresistanceoftheworkforce,thetotalworkisdoneanswerchooseDaboutthefirstcosmicvelocity,Inthefollowingstatement,thepositivereefis()AitistheminimumspeedthatanartificialearthsatellitefliesaroundtheearthBitisthespeedofthesatelliteonthenearearthorbitCItisthespeedofthesatelliteattheperigeewhenitrunsonellipticalorbitDitisalsocalledtheencirclingvelocity,thatis,thespeedofasatelliteorbitingroundtheearthisthefirstcosmicvelocityXi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter,Xi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenterFiftyfiveFiveAnalyticAnalyticsolutionAnalysis:thisquestionseemssimple,butbecausestudentsoftenfailtomakecleartheconceptThefirstcosmicspeed,thatis,kms,isoneAspecificvalueisthemaximumspeedatwhichanartificialsatellitemovesroundtheearthAsthestarmovesinacircle,thehighertheearthis,thelessitmovesItdoesnotorbitroundtheearthThefirstcosmicvelocityIfthesatelliteentersorbitneartheground,theorbitalvelocityisgreaterthankms,butlessthankms,ItsorbitaroundtheearthisnotacircleIt'sellipticalSothecorrectoptionforthisquestionisBanswer:B,twomanmadeearthsatellites,orbitinginacircularorbit,haveequalmass,theorbitalradiusratio,andrr=TheirkineticenergyratioisequaltoABCDanalysis:byGrMM=mrV:mv=GrmManswer:Casregardscurvilinearmotion,thefollowingistrueThemotionofaAcurvemustbeavariablespeedmotion,andtheBvariablemotionmustbecurvilinearmotionTheCcurvemotionmaybeauniformlyvariablemotion,andaDaccelerationmotionmustbecurvilinearmotionanalyticAnalyticsolutionAnalyticThespeedofthecurvemovesinthedirectionofthetangentofthecurve,andmustvary,sothecurvemustbemovingExerciseVariablespeedmotionmaybethedirectionofspeedunchanged,whilesizechangesmaybelinearmotionTheresultantforceofanobjectWhenaconstantforceofmagnitudeanddirectionremainsconstant,theobjectdoesauniformchangemotion,buttheforcemaynotbeinastraightlinewiththevelocitydirectionAtthispoint,theobjectissubjectedtoauniformspeedchangecurveObjectsthatundergoacceleratedmotionmayhavethesamemagnitudeofforce,butonlywhenthedirectionbeginsTheendisinastraightlinewiththevelocitydirection,atwhichpointtheobjectmovesinastraightlineThecorrectoptionisA,CasshowninFigure,thesmallsteelballmovesattheinitialspeedVonasmoothhorizontalsurfaceandisshownalongthesideofthemagnetThecurvemovestotheDpointAmagnetatA,closetothesmallsteelballmustbeNpoleBmagnetatB,closetothesmallsteelballmustbeSpoleCmagnetatC,closetothesmallsteelballmustbeNpoleTheDmagnetisatB,andthepolarityofthepolenearthesmallsteelballcannotbedeterminedanalyticAnalyticsolutionAnalyticAsmallsteelballisattractedbyamagnettodocurvilinearmotion,anditsdirectionofmotionisdeflectedonlyinthedirectionofattractionThemagnetpositionisonlypossibleatB,andcannotbeatAorCTheNpoleorSpoleofthemagnetattractsbothsmallsteelballsTherefore,thepolarityofthepolenearthesmallsteelballcannotbedeterminedThecorrectoptionisDTheparticleisatthreeconstantforcesF,BalancedinteractionofF,F,ifsuddenlyremovedF,whileFandFAparticle()Amustdoevenchangemotion,BmustdostraightlinemovementCmustdounevenmotion,DmustdocurvemotionanalyticAnalyticsolutionAnalyticTheconstantmotionofaparticleunderconstantforceandconstantaccelerationmustbeuniformlyvariablemotionBythequestionKnowable,WhensuddenlyfromFandmaintainingWhenFandFremainunchanged,theresultantforceofparticlesisF,andthedirectionisoppositetoF,ItmustbedoneevenlyvariablespeedmovementInthewaybeforeF,massbalance,therearetwopossibilities:oneisaparticleinastaticstate,itisremovedfromtheF,itmustbeinuniformrectilinearmotionthesecondistheparticleinuniformlinearmotion,isremovedfromtheF,theparticlemotioninastraightline(theconditionispossibleThedirectionandvelocityoftheFareinastraightline,anditmayalsobecurvedMove(theconditionisthatthedirectionandvelocityoftheFarenotinastraightline)ThecorrectoptionisA,asshowninFig,theobjectmovesalongthecurvefrompointAtoBatconstantforceF,whichsuddenlycausesittosufferThereverseforce,butthesizefromFtoFunchangedUndertheactionofforce,theobjectistransportedlaterInthefollowingstatement,whatiscorrectis()TheAobjectcannotmovealongthecurveBa,andtheBobjectcannotmoveBbalongthelineBBAACFigureDABCFigureVXi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter,Xi'anYifaneducationandcounselingcenterXi'anYifaneducationcounselingcenterCobjectcannotmovealongthecurveBc,DobjectcannotgobackalongtheoriginalcurveBAanalyticAnalyticsolutionAnalyticAnobjectmovingalongacurvefrompointAtopointB(exceptforpointB),anditsconstantforce,F,mustindicatethedirectionoftheconstantforceTotheinsideofthecurveWhenmovingtotheBpoint,thecurveoftheobjectmotionmustbedeterminedbythecurvemotionduetotheconstantforceWhenthedirectionoftheresultantforceisbent,theobjectcanonlymovealongtheBcThecorrectoptionsareA,B,andDelectricbicyclewindingmstandardrunwayshowninmotion,thecar'sspeedometerpointerhasbeendefinedinkmhStationaryWhatiscorrectinthefollowingstatementis()ThespeedoftheAelectriccarhasremainedthesameBelectriccarsalongthecurveBCDmovement,thecarhasbeenaccelerationCelectriccarsneedsaroundtherunwayaweek,andtheaveragespeedofelectriccarsinthissisequaltoWhentheDelectricvehiclemovesonthecurve,thedirectionoftheexternalforcecannotgoalongthetangentdirectionanalyticAnalyticsolutionAnalyticSpeedisthevector,notonlythesize,butalsothedirectionIntheprocessofmovingtheelectricvehicle,thespeedometerindicatoralwaysreferstothekmhThepositionofthevelocityremainsthesame,butthedirectionofthevelocitychangesduringthecourseofmovementAndgothroughthebendWhenthespeedanddirectionarealwaysinthetangentdirectionofthecurve,andchangeconstantly,italsohasacceleration,andthedirectionpointstothecurveInboardThisaccelerationisprovidedbytheexternalforceoftheelectricvehicle,andcanbededucedbyNewton'ssecondlawBendtotheinsideofthecurve,butnotalongthetangentThedisplacementoftheelectricvehiclearoundtherunwayinthecourseofoneweekiszero,andcanbedefinedbytheaveragespeedTheaveragespeediszerointhisprocessThecorrectoptionsareB,C,andDTwoFillintheblanks,asshownontheright,theuniformspeedofthecarontheflatroad,forsomereasontodouniformdecelerationmovement,Theobjectonthebackshelfofthecarriageaflewforwardandlandedonthefloorofthecaronthebackwalllm,Thevehicleisstilladvancing,andtheobjectisflyingats()thesizeofvehicleaccelerationfor()fromthefloorofthecarframedistanceisanalysis:whentheobjecthasjustfallen,thespeedisV,theobjectspeedisV,andthedisplacementdifferenceism,Vt(Vtat)=,a=msh=gt=manswer:()ms()m,knownasaroundthecenterofcelestialbodiestodouniformcircularmotionofthestarorbitradiusr,themotioncycleisT()massofcentralcelestialbodiesM=()ifthecentralbodyofradiusR,theaveragedensityof=()ifthestarsdouniformcircularmotionnearthesurfaceofthecentralbody,theaveragedensityoftheexpressionofRho=ThirteenThreeAnswerquestions,asshownontheright,alightspringwithanaturallengthofBandstiffnesscoefficientisfixedatpoints,andtheotherendisconnectedAballwithamassofMisusedTheballisoscillatingintheverticalface,andtheangularvelocityatthelowerisequaltoomegaTheamountofspringelongationchartBCDXi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter,Xi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenteranalysis:whentheballisplaceddirectlybelowtheOpoint,thespringisstretchedtox,andatthispointtheballisactedbytwoforcesactingasacircleTheradiusofactionisLxasshownontheright,oneendofthestringisattachedtoanobjectofmassM=kg,restingonthehorizontalsurfaceandpassingthroughasmoothholeattheotherendForobjectswithmassm=kg,thedistancebetweenthemidpointoftheMandthecircularholeism,andthemaximumstaticfrictionbetweentheMandthehorizontalsurfaceisknownTheforceisN,andnowtheplanerotatesaroundthecentralaxisInwhatrangeistheangularvelocityOmega,mwillbeatrest(g=ms)resolution:tomaketheMrest,theMshouldberelativelystationarywiththeplaneConsidertheMenergyandthehorizontalsurfaceInthetwoextremestatesofstillness,whenOmegaistheminimumoftherange,theMhasthecenteroftheloopDynamictrend,ThehorizontaldirectionofstaticfrictioninthedirectionofMdeviatesfromthecenterofthecircleThemagnitudeisequaltothemaximumstaticfrictionforceNForM,thereare:Tfm=M,Omega,r,TheOmega=rads,whenOmegaisthemaximumoftherange,Mhasthetendencytomoveawayfromthecenterofthecircle,andthedirectionofthefrictionalforcetowardthecenteroftheMinthehorizontaldirection,AndthesizeisN,atthistimethereisTfm=MOmegaR,Omega=,radsTherangeoftheOmega:rads<Omega<rads,asshownontheright,auniformslenderbarLOAcanbeturnedaroundthehorizontalaxisOthroughoneendoftheshaftintheverticalplaneTherodisinitiallyplacedinahorizontalpositionTherodisseparatedfromthepointbyLAsmallobjectmisplaced(asaparticle)TherodandthesmallobjectareinitiallyInastaticstateIftherodsuddenlywithangularvelocityaroundtheaxisrotatingataconstantspeed,askwhatthevalueofOmegarodOAandsmallobjectsOnceagaincollideanalysis:smallobjectsdofreefallmovement,rodOAandsmallobjectsmeetagainTherearetwocases,Oneisthesmallobjecttocatchtherod,thetwoistorotatetherod,afteraweektocatchupwithsmallobjects,thecolumnsolutionFigure,whenthetwoarejustagaincollides,ofsmallobjectsare:h=gtForathinrod,OAhas:theta=Omegaltorthetapi=OmegaTbythegeometricrelationofthegraph,theta=getsOmegal=LGPI,getOmega=LGSixpiTherefore,ifasmallobjectandarodmeetagain,theremustbeXi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter,Xi'anYifaneducationandcounselingcenterXi'anYifanEducationGuidanceCenter,asshown,theverticalcylinderwallsmooth,radiusofR,thetophasentranceA,intheAisjustbelow,hattheexitB,AballwithamassofMisshotfromthepopulationAalongthetangentialdirectionofthecylindricalwallhorizontally,andtheballisejectedfromtheBattheballWhataretheconditionsforspeedVOatentryAHowmuchpressuredoestheballholdonJaneduringthemovementanalysis:smallballintheverticaldirectionoffreefallmovement,sotheballinthebarrelmovementtimeis:HTG=Inthehorizontaldirection,thelawofcircularmotionisstudiedRTNVpi=(n=,)IISoTwoNRgVnRThPI(pi==n=,)Newton'ssecondlawofmotionTwoTwentytwonvNmgrfrequencymodulationRHPI(N=====L,,)inthequalityofMmotor,equippedwithamassofMunevenflywheel,flywheelrotationangularspeedisconstantOmega,Whenthecenterofgravityoftheflywheelisdirectlyabovetherotatingshaft,themotorhasnopressureontheground,and()thecenterofgravityoftheflywheelisawayfromtherotatingshaftDistance()themaximumpressureofthemotoronthegroundinthecourseofturninganalysis,becausetheflywheelmmakesuniformangularspeedrotation,andtheMisatrest,sotheisolationofMandMisanalyzedFormatthehighestpoint,T,m,Omegamg=rAtthispoint,theMpressureiszerozeromg,orT=ByeliminatingT:R=)(omegaMGeneralizedmomentestimatorWhenmgoestothelowestpoint,thedirectionofthemactingontheMisverticalanddownward,andtheMisthemaximumpressureontheground,Form,MondayMOmegamg=rForm,Mg,N=N=,MondaybyG,(MM)explanationthesubjectisvertical,flat,uniform,circularmotion,andMstatics,becauseofthemovementsofMandMDifferent,soitisnecessarytousetheisolationmethod,usingtheisolationmethod,whentheequationsofMandmareformulated,thegravityofallkindscanonlybetheselfgravity"Nomore"(MM),theword"gtotalgravity"misauniformangularrotationdrivenbyanelectricmotor,m,inthesubjectTheuniformmotionofaverticalplaneisnotaconservationcategoryofmechanicalenergy,theShenzhoufivemannedspacecraftinorbittheearthfifthcircleoftheorbit,theellipticalorbitoftheoriginaltoaheightfromthegroundH======kmcircularorbitTheknownradiusoftheearthisr*km,thegroundaccelerationofgravityisgmthereflectionstestleadsTheformulafortheperiodTofthespacecraftrunningabovethecircularorbit(expressedinH,R,g),andthencalculatesthevalueoftheperiodTLeavetwosignificantdigits)Xi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter,Xi'anYifaneducationandcounselingcenterXi'anYifaneducationandcounselingcenter,analysis:setearthqualityism,thespacecraftmassism,speedisV,roundorbitradiusisr,bygravitationandcattleThesecondlawofDaytonhasRVMRMmG=V=RTPI=MgnearthegroundRMmG=BytheknownconditionsR=RGHRHRMonday)(Pi=ThesubstitutionvalueisT=*

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