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机械课程设计说明书范例(油田抽油机)机械原理机械设计课程设计计算说明书设计题目油田抽油机天津大学机械工程学院机械设计制造及自动化专业1班级设计人李廷江指导教师陈树昌、王多2006年01月08日目录1、设计题目12、系统总体方案的确13、设计原始数据24、电动机的选择35、传动比的分配46、执行机构尺寸计算57、机构运动分析68、V带设计159、传动装置的运动和动力参数1710、齿轮的传动计算1811、减速器机体的尺寸设计3112、轴的设计3213、键的选择及强度较核3314、轴承寿命计算及静强度3515、轴的强度较核3716、参考文献41 计算及说明...

机械课程设计说明书范例(油田抽油机)
机械原理机械设计课程设计计算说明书设计 快递公司问题件快递公司问题件货款处理关于圆的周长面积重点题型关于解方程组的题及答案关于南海问题 目油田抽油机天津大学机械工程学院机械设计制造及自动化专业1班级设计人李廷江指导教师陈树昌、王多2006年01月08日目录1、设计题目12、系统总体 方案 气瓶 现场处置方案 .pdf气瓶 现场处置方案 .doc见习基地管理方案.doc关于群访事件的化解方案建筑工地扬尘治理专项方案下载 的确13、设计原始数据24、电动机的选择35、传动比的分配46、执行机构尺寸计算57、机构运动分析68、V带设计159、传动装置的运动和动力参数1710、齿轮的传动计算1811、减速器机体的尺寸设计3112、轴的设计3213、键的选择及强度较核3314、轴承寿命计算及静强度3515、轴的强度较核3716、参考文献41 计算及说明 主要结果 1、设计题目:油田抽油机2、系统总体方案的确定:系统总体方案:电动机传动系统执行机构;初选三种传动方案,如下:(a)二级圆柱齿轮传动(b)为涡轮涡杆减速器(c)为二级圆柱圆锥减速器系统方案总体评价:)方案为整体布局最小,传动平稳,而且可以实现较大的传动比,但是抽油机要求长时间的工作,由于涡杆传动效率低,功率损失大,很不经济图c方案布局比较小,但是圆锥齿轮加工较困难,特别的是大直径,大模数的锥轮,所以一般不采用图a布局一般,传动效率好,加工比较方便,且适合长期的工作环境最终方案确定:电动机传动系统执行机构如下图)3、设计原始数据:每日抽油量12.3冲程0.4摇杆长度1.51许用压力角32行程速比系数1.08平衡重840泵筒和活塞的直径0.038下泵深度300抽油杆直径不同直径抽油杆连接长度4、电动机的选择:1.每日抽油量的计算:其中,,,,;则,那么;2.抽油机最大负荷的计算:式中,为液柱质量负荷:其中,为抽油杆的总长度单位:),等于下井深度300;为抽油杆质量负荷:其中,、和、分别为不同直径抽油杆的每米长质量及连接长度,由原始数据查取;,,;则,3.电动机所需功率:式中,为传动装置的总效率,为曲柄轴转速,为曲柄轴上的最大转矩,可由下式计算:代入数据可得:又知,带传动效率,轴承传动效率,齿轮传动效率,联轴器传动效率,则传动装置总效率:那么,综上,选择电动机,额定功率,额定转速;5、传动比分配:电动机满载转速;那么,机构总传动比;取带传动传动比;则高速齿轮传动比与低速齿轮传动比为又因为则,,;6、执行机构尺寸计算:执行机构如下图:根据原始数据有:,;行程速比系数;则,由于,则点位于圆内,如下图:,其中;其中,由于,则:解得:,;7、机构运动分析:1数学模型如图所示,取以A点为原点、轴与AD线一致的直角坐标系,标出向量和转角,由封闭向量多边形ABCD可得即摆角分析:由式的实部和虚部分别相等可得经计算解得速度分析:将式对时间求导可得实部和虚部分别相等可得解得加速度分析:将式对时间求二阶导可得实部和虚部分别相等可得解得2框图设计3程序和计算结果VisualC++程序includstdiohincludmathhoidmain(){floatab=01437893,bc=12614775,cd=15,ad=141093,pi=3141593,w1=21894,w2,w3,1,2,3,r,k,a,b,c,p1,p2,p3,t,t1,t2,t3;r=(bcbccdcd(adab)(adab))(2cd(adab));p3=atan(sqrt(1rr)r);if(p3<0)p3=p3+pi;for(p1=0;p1<=2pi;p1+=pi18){t=adad+cdcd+ababbcbc;a=sin(p1);b=adabcos(p1);c=t(2abcd)adcdcos(p1);t1=2atan((a+sqrt(aa+bbcc))(bc));t2=2atan((asqrt(aa+bbcc))(bc));if(fabs(t1p3)<fabs(t2p3))p3=t1;lsp3=t2;p2=atan((cdsin(p3)absin(p1))(ad+cdcos(p3)abcos(p1)));w2=absin(p1p3)w1(bcsin(p2p3));w3=absin(p1p2)w1(cdsin(p3p2));2=(abw1w1cos(p1p3)+bcw2w2cos(p3p2)cdw3w3)(bcsin(p3p2));3=(abw1w1cos(p1p2)+bcw2w2cdw3w3cos(p3p2))(cdsin(p3p2));k=180pi;printf(p1=%f\n,p1k);printf(p2=%f\tp3=%f\tw2=%f\n,p2k,p3k,w2);printf(w3=%f\t2=%f\t3=%f\n,w3,2,3);printf(\n);}}计算结果:p1=0000000p2=72769769p3=126559019w2=2484431w3=24844302=449135133=18783482p1=10000000p2=71561406p3=125466243w2=2788365w3=22839082=310819233=31369448p1=20000000p2=70240175p3=124487245w2=2977327w3=19880322=162513813=42553314p1=30000001p2=68859739p3=123662513w2=3047687w3=16113952=14979383=51513309p1=40000001p2=67473545p3=123024492w2=3003909w3=11741452=122486393=57694626p1=50000001p2=66131434p3=122595624w2=2856885w3=06995702=243181513=60866100p1=60000001p2=64877241p3=122387481w2=2621666w3=02115482=343371623=61103199p1=69999998p2=63747411p3=122401019w2=2315181w3=02676442=421991923=58717686p1=79999995p2=62770612p3=122627699w2=1954367w3=07188512=479948503=54165222p1=89999992p2=61967983p3=123051075w2=1554923w3=11268292=519309083=47958050p1=99999988p2=61353963p3=123648744w2=1130682w3=14804112=542589653=40598618p1=109999985p2=60937083p3=124394013w2=0693467w3=17722542=552239693=32538250p1=119999989p2=60720928p3=125257649w2=0253286w3=19983392=550334783=24157602p1=129999986p2=60884558p3=126209258w2=0181308w3=21573772=538444523=15762409p1=139999982p2=60884558p3=127218323w2=0602811w3=22502382=517625123=7587976p1=149999979p2=61252480p3=128255132w2=1004373w3=22794082=488487633=0192447p1=159999976p2=61798014p3=129291394w2=1379493w3=22485402=451305813=7458399p1=169999973p2=62507637p3=130300691w2=1721789w3=21620682=406137123=14133546p1=179999969p2=63364887p3=131258707w2=2024881w3=20248822=352938963=20177828p1=189999966p2=64350401p3=132143449w2=2282351w3=18420722=291673013=25579956p1=199999963p2=65441872p3=132935245w2=2487778w3=16187312=222392693=30349710p1=209999960p2=66614082p3=133616734w2=2634848w3=13598152=145318543=34509365p1=219999957p2=67838974p3=134172739w2=2717513w3=10700872=60906953=38083851p1=229999953p2=69085859p3=134590268w2=2730206w3=07541372=30074653=41089523p1=239999950p2=70321611p3=134858339w2=2668124w3=04164992=126458863=43521774p1=249999947p2=71511211p3=134968142w2=2527592w3=00618722=226562653=45342010p1=259999944p2=72618276p3=134913063w2=2306530w3=03045622=328050123=46465389p1=269999941p2=73605948p3=134689046w2=2005025w3=06767262=427783813=46751263p1=279999937p2=74438029p3=134295122w2=1626032w3=10471872=521701353=45999798p1=289999934p2=75080490p3=133734104w2=1176126w3=14067002=604780203=43959549p1=299999931p2=75503258p3=133013506w2=0666233w3=17438862=671174853=40351479p1=309999928p2=75682339p3=132146536w2=0112142w3=20451742=714621733=34914249p1=319999924p2=75602091p3=131153044w2=0465430w3=22951952=729172443=27471275p1=329999921p2=75257385p3=130060160w2=1041487w3=24777802=710227433=18011518p1=339999918p2=74655161p3=128902238w2=1588289w3=25775862=655692523=6764577p1=349999915p2=73815239p3=127720069w2=2077758w3=25822172=566932723=5758087p1=359999912p2=72769783p3=126559032w2=2484429w3=24844312=449135783=18783415角度:速度:加速度:程序标识符的说明:程序中的符号 公式 小学单位换算公式大全免费下载公式下载行测公式大全下载excel公式下载逻辑回归公式下载 中的符号说明AB杆1的长度BC杆2的长度CD杆3的长度AD机架4的长度W1杆1的角速度PI圆周率RRP3杆3的转角AA公式中间变量BB公式中间变量CC公式中间变量P1杆1的转角P2杆1的转角W2杆2的角速度W3杆3的角速度E2杆2的角加速度E3杆3的角加速度8、带设计:1普通带型号查表174,得按式1715),根据和,由图1711选取B型带2带轮基准直径由图1711并参照表175选取3带速4中心距、带长及包角根据式1718)初步确定中心距根据式1719)初步计算带的基准长度由表179,选带的基准长度按式1721)计算实际中心距,圆整取根据式1722)验算小轮包角5带的根数按式1723)由表173,查得由表177,查得由表178,查得由表179,查得取根6初拉力按式1724)由表171查得7作用在轴上的载荷按式1725)9、传动装置的运动和动力参数:1各轴转速Ⅰ轴Ⅱ轴Ⅲ轴2各轴输入功率Ⅰ轴Ⅱ轴Ⅲ轴曲柄转盘则为:ⅠⅢ轴的输出功率则分别是输入功率乘轴承效率;3各轴输入转矩电动机的输出转矩:Ⅰ轴Ⅱ轴Ⅲ轴曲柄转盘ⅠⅢ轴的输出转矩则分别为各轴的输入转矩乘轴承效率;运动和动力参数计算结果整理于下表: ,,电动机 轴名 效率 转矩 转速 传动比 效率 输入 输出 输入 输出 电机轴 258358 2570 960 400 096 Ⅰ轴 248024 244304 98688 97208 240 370167 095545 Ⅱ轴 236974 233419 349036 343801 648356 296134 095545 Ⅲ轴 226417 223021 987566 972753 218940 100 095545 曲柄转轴 220790 217478 963025 948580 218940 10、齿轮的传动计算Ⅰ高速级齿轮一)选择材料,确定许用应力1.材料大,小齿轮均采用选用40Cr表面淬火,齿面硬度为4855HRC,平均取齿面硬度50HRC2.确定许用弯曲应力(1)总共作用时间由已知,总共作用时间(2)寿命系数YN由式1817)及表1810,弯曲应力循环次数由图1825,取寿命系数(3)弯曲疲劳极限由图18-8,取极限应力(4)尺寸系数估计模数,由图1826,取尺寸系数(5)安全因数参照表1811,取安全因数(6)计算许用弯曲应力由式(1821),显然故3确定许用接触应力(1)寿命系数接触应力循环次数,由图1821,取接触强度计算的寿命系数,(2)接触疲劳极限由图184,取极限应力(3)安全因数参照表1811,取安全因数(4)许用接触应力由式(1816)及,许用接触应力二)选择齿数,齿宽系数及精度等级1)初取齿数初取小齿轮齿数,则大齿轮齿数圆整取2)选择齿宽系数及精度等级取齿宽系数,初估小齿轮直径,则齿宽取大齿轮齿宽齿轮圆周速度选6级精度等级三)确定载荷系数1)使用系数由表187,取2)动载系数由表1814,取3)齿向载荷分布系数由图1816,取4)齿间载荷分配系数由齿轮切向力及条件查表188,取5)计算由式(188)及式(189),载荷系数四)重合度计算初估螺旋角,依据式1829)及表85中公式可求得1)端面重合度2)纵向重合度3)总重合度五)齿根抗弯疲劳强度计算1)齿形系数当量齿数查图1823,取2)应力修正系数由图1824,取3)重合度系数端面压力角基圆螺旋角由式1833)可得当量齿轮端面重合度于是,由式1832)可得重合度系数4)螺旋角系数查图1828,取5)由齿根抗弯疲劳强度条件求模数由于故由式1831),为满足齿根抗弯疲劳强度条件,则需使模数取 标准 excel标准偏差excel标准偏差函数exl标准差函数国标检验抽样标准表免费下载红头文件格式标准下载 模数六)确定主要参数1)中心距初算中心距圆整取2)螺旋角满足几何条件的螺旋角与初取相差较大改取,则螺旋角3)验算传动比误差实际齿数比传动比误差满足使用要求4)计算分度圆直径与初估相差不大5)齿轮宽度取大齿轮齿宽小齿轮齿宽七)齿面接触疲劳强度验算1)弹性系数查表189,2)节点区域系数查图1820,取3)重合度系数由式1828)4)螺旋角系数由式1827),5)校核齿面接触疲劳强度由式1826),齿面接触应力故,齿面接触疲劳强度足够;八)齿面静强度验算1)确定许用接触应力参照表1811,取静强度安全因数;由图1821,取寿命系数;于是由式1822),许用接触应力2)校核齿面静强度根据过载条件,由式1822),齿面最大接触应力齿面静强度足够九)齿根抗弯静强度验算1)确定许用接触应力参照表1811,取静强度安全因数;由图1825,取寿命系数;于是由式1823),许用接触应力2)计算齿根弯曲应力由式1818),及3)求最大弯曲应力并校核强度由式1822),最大弯曲应力静强度满足要求Ⅱ低速级齿轮一)选择材料,确定许用应力1.材料大,小齿轮均采用选用40Cr表面淬火,齿面硬度为4855HRC,平均取齿面硬度50HRC2.确定许用弯曲应力(1)总共作时间由已知,总共作时(2)寿命系数YN由式1817)及表1810,弯曲应力循环次数由图1825,取寿命系数(3)弯曲疲劳极限由图18-8,取极限应力(4)尺寸系数估计模数,由图1826,取尺寸系数(5)安全因数参照表1811,取安全因数(6)计算许用弯曲应力由式(1821),显然故3确定许用接触应力(1)寿命系数接触应力循环次数,由图1821,取接触强度计算的寿命系数,;(2)接触疲劳极限由图184,取极限应力(3)安全因数参照表1811,取安全因数(4)许用接触应力由式(1816)及,许用接触应力二)选择齿数,齿宽系数及精度等级1)初取齿数初取小齿轮齿数,则大齿轮齿数圆整取2)选择齿宽系数及精度等级取齿宽系数,初估小齿轮直径,则齿宽取大齿轮齿宽齿轮圆周速度选6级精度等级三)确定载荷系数1)使用系数由表187,取2)动载系数由表1814,取3)齿向载荷分布系数由图1816,取4)齿间载荷分配系数由齿轮切向力及条件查表188,取5)计算由式(188)及式(189),载荷系数四)重合度计算初估螺旋角,依据式1829)及表85中公式可求得1)端面重合度2)纵向重合度3)总重合度五)齿根抗弯疲劳强度计算1)齿形系数当量齿数查图1823,取2)应力修正系数由图1824,取3)重合度系数端面压力角基圆螺旋角由式1833)可得当量齿轮端面重合度于是,由式1832)可得重合度系数4)螺旋角系数查图1828,取5)由齿根抗弯疲劳强度条件求模数由于故由式1831),为满足齿根抗弯疲劳强度条件,则需使模数取标准模数六)确定主要参数1)中心距初算中心距圆整取2)螺旋角满足几何条件的螺旋角3)验算传动比误差实际齿数比传动比误差满足使用要求4)计算分度圆直径与初估相差不大5)齿轮宽度取大齿轮齿宽小齿轮齿宽七)齿面接触疲劳强度验算1)弹性系数查表189,2)节点区域系数查图1820,取3)重合度系数由式1828)4)螺旋角系数由式1827),5)校核齿面接触疲劳强度由式1826),齿面接触应力齿面接触疲劳强度足够八)齿面静强度验算1)确定许用接触应力参照表1811,取静强度安全因数;由图1821,取寿命系数;于是由式1822),许用接触应力2)校核齿面静强度根据过载条件,由式1822),齿面最大接触应力齿面静强度足够九)齿根抗弯静强度验算1)确定许用接触应力参照表1811,取静强度安全因数;由图1825,取寿命系数;于是由式1823),许用接触应力2)计算齿根弯曲应力由式1818),及3)求最大弯曲应力并校核强度由式1822),最大弯曲应力静强度满足要求11、减速器机体的尺寸设计机座壁厚度:机盖壁厚度:机座凸缘厚度:EMBEDEquationDSMT4机盖凸缘厚度:机座底凸缘厚度:地脚螺钉直径:地脚螺钉数目:轴承旁联接螺栓直径:机盖与机座联接螺栓直径:联接螺栓间距:轴承端盖螺钉直径:窥视孔盖螺钉直径:定位销直径:至外壁距离:至凸缘边缘距离:轴承旁凸台半径:轴承旁凸台高度:外机壁至轴承座端面距离:大齿顶圆与内机壁距离:齿轮端面与内机壁距离:机盖机座肋板厚度:地脚沉头座直径:40mm12、轴的设计由式202)各轴的直径,查表203,对于40Cr材料的轴C=10698轴上有键槽时,会削弱轴的强度对于直径的轴,单键时轴径增大5%7%,双键时增大10%15%,故中间轴各轴段设计:1各段轴的直径轴段1为轴承径,其直径应符合轴承内径标准,且,由此选定因此,轴承代号为32007轴段2与齿轮配合,且便于安装,取其标准系列轴段3为定位轴肩,轴肩高度取,则轴段4与齿轮配合,轴段5为轴承径,直径与相同2各段轴的长度轴段2的长度取决与轮毂宽度轮毂宽度l=62mm,取轴段2的长度略小于轮毂宽度轴段1的长度由轴承宽度,和实际位置尺寸确定:轴段3为两轴间位置取轴段5的长度由轴承宽度,和实际位置尺寸确定:轴段4的长度取决与轮毂宽度轮毂宽度l=44mm,取轴段4的长度略小于轮毂宽度13、键的选择及强度校核一)连接带轮处1确定键的类型和尺寸带轮要求一定的对中性由于是静连接,选用A型普通平键由设计手册查得当轴径时,键取为参照带轮轮毂宽度,及普通平键的长度系列,取键长2强度验算因是静连接,故只验算挤压强度,由式151)式中由表151查取许用挤压应力为故,满足强度要求二)Ⅱ轴大轮处1确定键的类型和尺寸6级精度的齿轮要求一定的对中性由于是静连接,选用A型普通双平键由设计手册查得当轴径时,键取为参照齿轮轮毂宽度,及普通平键的长度系列,取键长2强度验算因是静连接,故只验算挤压强度,由式151)式中由表151查取许用挤压应力为,此处用双平键,按15倍强度计算故,满足强度要求二)Ⅲ轴大轮处1确定键的类型和尺寸6级精度的齿轮要求一定的对中性由于是静连接,选用A型普通双平键由设计手册查得当轴径时,键取为参照齿轮轮毂宽度,及普通平键的长度系列,取键长2强度验算因是静连接,故只验算挤压强度,由式151)式中由表151查取许用挤压应力为,此处用双平键,按15倍强度计算故,满足强度要求14、轴承寿命计算及静强度由于中间轴有两个齿轮,所受动载荷比较大,所以这里只需要校核中间轴二轴承的寿命一)两轴承所受径向载荷由上,轴强度的计算知1轴垂直面支反力2轴水平面支反力3两轴承所受的径向载荷即合成后的支反力二)计算轴承所受的轴向载荷1计算内部轴向力轴承型号32009,为圆锥滚子轴承,由标准查得性能参数为由表2111,圆锥滚子轴承的内部轴向力,则2计算轴承所受的轴向载荷轴上个轴向力的方向由式218),219)可列出取两者中较大者取两者中较大者三)计算当量动载荷由式215),由表218取冲击载荷因数系数X,Y与判断因子有关,由手册中查的32009轴承,轴承Ⅰ故,则轴承Ⅱ故,则(四)寿命计算因,且两轴承型号相同,故只按Ⅰ轴承计算寿命即可取由式217)有寿命高于43800,故满足寿命要求五)静强度计算1计算轴承静载荷由式2113),当量静载荷,由表2113,32009型圆锥滚子轴承,故2验算静强度因,且两轴承型号相同,故只按Ⅰ轴承计算寿命即可取由表2114,取静强度安全因数由式2114)故满足静强度要求15、轴的强度校核1.画轴的空间受力图将齿轮所受载荷简化为集中力,并通过轮毂中截面作用于轴上轴的支点反力也简化为集中力通过载荷中心作用于轴上;2.作垂直平面受力图和水平平面受力图,求出作用于轴上的载荷齿轮Ⅰ切向力:径向力:轴向力:齿轮II切向力:径向力:轴向力:在垂直平面受力:EMBEDEquationDSMT4在水平平面受力:3.作出垂直平面弯矩和水平平面弯矩图垂直平面弯矩:截面I:截面II:水平平面弯矩:截面I:截面II:4.求合成弯矩M及作出合成弯矩阵图5.作出转矩阵图根据条件,取转矩6作出当量弯矩图,并确定可能的危险截面已知材料为40Cr钢调质,由表20—1查得用插值法由表204查得[],由已知条件,轴的转矩可按脉动循环考虑,即则截面I:EMBEDEquationDSMT4EMBEDEquationDSMT47.校核轴径截面Ⅰ有双键,最小轴径应增大15%;EMBEDEquationDSMT4结论:按当量弯矩法校核,轴的强度足够16、参考文献《机械原理与机械设计》 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格式:doc
大小:2MB
软件:Word
页数:44
分类:生产制造
上传时间:2017-03-29
浏览量:91