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高考数学数列大题训练高考数学数列大题训练 已知等比数列 分别是某等差数列的第5项、第3项、第2项,且 (Ⅰ)求 ;(Ⅱ)设 ,求数列 2.已知数列 满足递推式 ,其中 (Ⅰ)求 ; (Ⅱ)求数列 的通项公式; (Ⅲ)求数列 的前n项和 3.已知数列 的前 项和为 ,且有 , EMBED Equation.DSMT4 (1)求数列 的通项公式; (2)若 ,求数列 的前 项的和 。 4.已知数列{ }满足 ,且 . (Ⅰ)求 , ;(Ⅱ)证明数列{ }是等差数列; (Ⅲ)求数列{ }的前 ...

高考数学数列大题训练
高考数学数列大题训练 已知等比数列 分别是某等差数列的第5项、第3项、第2项,且 (Ⅰ)求 ;(Ⅱ)设 ,求数列 2.已知数列 满足递推式 ,其中 (Ⅰ)求 ; (Ⅱ)求数列 的通项公式; (Ⅲ)求数列 的前n项和 3.已知数列 的前 项和为 ,且有 , EMBED Equation.DSMT4 (1)求数列 的通项公式; (2)若 ,求数列 的前 项的和 。 4.已知数列{ }满足 ,且 . (Ⅰ)求 , ;(Ⅱ)证明数列{ }是等差数列; (Ⅲ)求数列{ }的前 项之和 5.已知数列 满足 , . (1)求 , , ; (2)求证:数列 是等差数列,并写出 的一个通项。 6.数列 的前 项和为 , , HYPERLINK "http://wxc.833200.com"   (Ⅰ)求数列 的通项 ; (Ⅱ)求数列 的前 项和 7. . 求证: ⑴数列{bn+2}是公比为2的等比数列; ⑵ EMBED Equation.3 ; ⑶ EMBED Equation.3 . 8.已知各项都不相等的等差数列 的前六项和为60,且 的等比中项. (1)求数列 的通项公式 ; (2)若数列 的前n项和Tn. 9.已知 是数列 的前 项和, ,且 ,其中 . 求证数列 是等比数列; 求数列 的前 项和 . 10.已知 是数列{ }的前n项和,并且 =1,对任意正整数n, ;设 ). (I)证明数列 是等比数列,并求 的通项公式; (II)设 的前n项和,求 . 高考数列大题参考 答案 八年级地理上册填图题岩土工程勘察试题省略号的作用及举例应急救援安全知识车间5s试题及答案 1.解析: 设该等差数列为 ,则 , , EMBED Equation.DSMT4 EMBED Equation.DSMT4 EMBED Equation.DSMT4 即: EMBED Equation.DSMT4 , EMBED Equation.DSMT4 , EMBED Equation.DSMT4 , EMBED Equation.DSMT4 EMBED Equation.DSMT4 , 的前 项和 当 时, , EMBED Equation.DSMT4 (8分) 当 时, , EMBED Equation.DSMT4 EMBED Equation.DSMT4 2.解:(1)由 知 解得: 同理得 (2)由 知 EMBED Equation.3 构成以 为首项以2为公比的等比数列; ; 为所求通项公式 (3) EMBED Equation.3 3.解:由 , ,又 , , 是以2为首项, 为公比的等比数列, , (1) (2) (1)—(2)得 即: , 4.解:(Ⅰ) , . (Ⅱ) , ∴ , 即 . ∴数列 是首项为 ,公差为 的等差数列. (Ⅲ)由(Ⅱ)得 ∴ . EMBED Equation.3 EMBED Equation.3 . ∴ . 5.解: (1) (2)证明:由题设可知 是以 为首项, 为公差的等差数列 故 6.解:(Ⅰ) , , HYPERLINK "http://wxc.833200.com"   又 , 数列 是首项为 ,公比为 的等比数列, HYPERLINK "http://wxc.833200.com"   当 时, , (Ⅱ) , 当 时, ; 当 时, ,…………① ,………………………② 得: EMBED Equation.DSMT4 HYPERLINK "http://wxc.833200.com"   HYPERLINK "http://wxc.833200.com"  又 也满足上式, 7.解: ⑴ 数列{bn+2}是首项为4公比为2的等比数列; ⑵由⑴知 …… 上列(n-1)式子累加: ⑶ EMBED Equation.3 . 8.解:(1)设等差数列 的公差为 ,则 解得 . (2)由 EMBED Equation.3 9.解:① EMBED Equation.DSMT4 EMBED Equation.DSMT4 EMBED Equation.DSMT4       EMBED Equation.DSMT4 又 也满足上式, EMBED Equation.DSMT4       EMBED Equation.DSMT4 ( ) 数列 是公比为2,首项为 的等比数列 (2)由①, EMBED Equation.DSMT4 于是 EMBED Equation.DSMT4 EMBED Equation.DSMT4 10.解析:(I) 两式相减: 是以2为公比的等比数列, EMBED Equation.3 (II) EMBED Equation.3 而 EMBED Equation.3 _1234567953.unknown _1234568017.unknown _1234568049.unknown _1234568081.unknown _1234568097.unknown _1234568113.unknown _1234568121.unknown _1234568129.unknown _1234568133.unknown _1234568137.unknown _1234568139.unknown _1234568140.unknown _1234568141.unknown _1234568138.unknown _1234568135.unknown _1234568136.unknown _1234568134.unknown _1234568131.unknown _1234568132.unknown _1234568130.unknown _1234568125.unknown _1234568127.unknown _1234568128.unknown _1234568126.unknown _1234568123.unknown _1234568124.unknown _1234568122.unknown _1234568117.unknown _1234568119.unknown _1234568120.unknown _1234568118.unknown _1234568115.unknown 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_1234567957.unknown _1234567959.unknown _1234567960.unknown _1234567958.unknown _1234567955.unknown _1234567956.unknown _1234567954.unknown _1234567921.unknown _1234567937.unknown _1234567945.unknown _1234567949.unknown _1234567951.unknown _1234567952.unknown _1234567950.unknown _1234567947.unknown _1234567948.unknown _1234567946.unknown _1234567941.unknown _1234567943.unknown _1234567944.unknown _1234567942.unknown _1234567939.unknown _1234567940.unknown _1234567938.unknown _1234567929.unknown _1234567933.unknown _1234567935.unknown _1234567936.unknown _1234567934.unknown _1234567931.unknown _1234567932.unknown _1234567930.unknown _1234567925.unknown _1234567927.unknown _1234567928.unknown _1234567926.unknown _1234567923.unknown _1234567924.unknown _1234567922.unknown _1234567905.unknown _1234567913.unknown _1234567917.unknown _1234567919.unknown _1234567920.unknown _1234567918.unknown _1234567915.unknown _1234567916.unknown _1234567914.unknown _1234567909.unknown _1234567911.unknown 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