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快递公司问题件快递公司问题件货款处理关于圆的周长面积重点题型关于解方程组的题及答案关于南海问题
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26, book chizhe paper will work, art chizhe technology will yield -- Pu Songling
The magnetic field of electromagnetic induction the choice of college entrance examination questions
Fig. 1. diagram of a filter speed device
A and B are parallel metal plates placed horizontally. A bunch of electrons with different speeds enter the A and B two plates in a horizontal direction through a small hole O
In order to select an electron with a certain rate, a voltage can be added between a and B and a uniform magnetic field is added along the direction perpendicular to the paper, so that the selected electrons can still move along the horizontal line 'OO' and be ejected by 'O'
Gravity action
The possible way to achieve the above objective is to
A. makes the a plate potential higher than the B plate and the magnetic field perpendicular to the direction of the foil
B. makes the a plate potential lower than the B plate, and the field direction is perpendicular to the surface
The C. makes the a plate potential higher than the B plate and the field direction perpendicular to the paper surface
The D. causes the a plate potential to fall below the B plate and the field direction perpendicular to the paper surface
2. as shown in the diagram, the direction of the uniform magnetic field is perpendicular to the surface of the paper. A charged particle is injected from the magnetic field boundary D point perpendicular to the magnetic field direction, along the curve DPA, hits the a point on the screen MN, and passes through the PA section for t
If the particle passes through the point of P, it is collided with a stationary uncharged particle and combined with a new particle and eventually hits the screen MN
The gravity of the two particles is neglected
New particle movement
The A. trajectory is Pb, and the time to the screen will be less than t
The B. track is PC, and the time to the screen will be greater than t
The C. trajectory is Pb, and the time to the screen will equal t
The D. track is PA, and the time to the screen will be greater than t
3. as shown above, a uniform magnetic field above the plate MN placed at a horizontal level has a magnetic induction magnitude of B, and the field direction is perpendicular to the surface of the paper
Many particles with a mass of M and a charge of +q are injected into the magnetic field at the same rate V in all directions within the sheet, in the direction of the O
Irrespective of gravity, the interaction between particles is neglected
The shaded part in the following figure indicates the region in which the charged particles may pass, wherein R=
Which map is correct?
(indefinite choice)
4. as shown, the square area ABCD is full of uniform magnetic field. The direction of the magnetic field is perpendicular to the surface
A hydrogen nucleus enters the magnetic field at a certain speed from the midpoint of the ad side, along the direction perpendicular to the ad and perpendicular to the magnetic field. The magnetic field is ejected from the N at the AB side of the M
If the magnetic induction of the magnetic field is changed to 2 times the original, and the other conditions remain the same,
then the position of the hydrogen nucleus to shoot out the magnetic field is ()
A. is somewhere between B and n
B. is somewhere between N and a
C.a point
D. is somewhere between a and M
5. as shown in the x>0 and y>0 space, there is a constant uniform magnetic field. The direction of the magnetic induction is perpendicular to the oxy plane, and the size is B
A mass of M existing electricity charged particle of Q, on the X axis to the distance from the origin of x0 P, with initial velocity parallel to the Y axis into the magnetic field, the magnetic field emitted perpendicular to the Y axis in the direction of magnetic field
Regardless of gravity
It is by these terms that...
A. cannot determine the position of the particle passing through the Y axis
B. does not determine the size of the particle velocity
C. does not determine the time experienced by particles moving
in a magnetic field
D. above three judgments are wrong
The equation of 6.K meson decay is K - Pi Pi + PI 0, in which K meson and pion band are negatively charged by elementary elements, and PI 0 meson is not charged
A K meson in the direction perpendicular to the direction of the magnetic field into the magnetic field, the arc trajectory AP, PI meson decay after the arc trajectory is PB, the two track on their tangent point P, and the radius ratio is 2: 1
The trajectories of PI 0 mesons are not drawn
From this we can see that the ratio of the pion momentum size to the momentum size of PI 0 is...
A.1: 1 B.1: 2
C.1: 3 D.1: 6
There is a uniform electric field and the magnetic field in the 7. dotted line shows the area. Make the coordinate figure. A charged particle along the X axis is the direction of movement in the process of entering the area, the region through the direction always do not deflect. Without the effects of gravity, electric field intensity E and magnetic induction of B direction may be............ (...)
(indefinite choice)
Both A.E and B follow the X axis
B.E is positive along the Y axis and the B is positive along the Z axis
C.E is positive along the Z axis and the B is positive along the Y axis
Both D.E and B are in the direction of the Z axis
Figure 8. is a P lead before and after the trajectory of particles through the chamber. The chamber of the uniform magnetic field direction and the vertical plane trajectory (figure in the direction perpendicular to the surface), the particle
A. must be positively charged. B. must be negatively charged
C. is not charged, D. may be positively charged or negatively charged
9. electromagnetic flowmeter is widely used to measure the flow of a conductive fluid (such as sewage) in a pipe (volume of fluid through the cross section of the pipe within unit time)
In order to simplify, suppose that the flowmeter is a section of rectangular pipe with a rectangular cross section as shown in the figure. The length, width and height of the empty part are a, B and C in the figure respectively
The two ends of the flowmeter are connected to the pipe conveying fluid (dashed in the figure)
The upper and lower sides of the flowmeter are metal materials, and the front and rear sides are insulated
A uniform magnetic field with a magnetic flux density of B is added to the flowmeter. The direction of the magnetic field is perpendicular to the front and back sides
When the conducting fluid flows steadily through the flow meter, the upper and lower two surfaces of the flowmeter are connected with both ends of a current meter with a resistance R, and the I represents the measured current value outside the tube
The resistivity of a known fluid, excluding the internal resistance of the ammeter, can be determined by the flow rate
A. (bR+) B. (aR+)
C. (cR+) D. (R+)
In figure 10., placing a series with a resistor R rectangular metal guide AOB fixed in a uniform magnetic field (on paper in), the magnetic field perpendicular to the direction toward the paper, another two metal guide C and D respectively, OB placed parallel to the OA
Keep the rail in good contact, and the resistance of the metal rail shall not be counted
The following four steps: 1. The rate of V mobile D and ob, making it a distance increases to V times; the rate of mobile C, making it the distance between a and OA is reduced by half; and then again, at a rate of 2V mobile C, making it back; finally, at a rate of 2V mobile D. Make it back to the original place
In the four processes mentioned above, the quantity of electric resistance through the resistance R is Q1, Q2, Q3 and Q4 in turn
A. Q1 = Q2 = Q3 = Q4
B. Q1 = Q2 = 2Q3 = 2Q4
C. 2Q1 = 2Q2 = Q3 = Q4
D. Q1 = Q2 = Q3 = Q4
11. as shown,
The smooth metal guide rail is arranged in a horizontal plane, two parallel, in a uniform magnetic field, the magnetic field direction perpendicular to the plane of the guide rail, guide rail is connected with a metal rod resistance; ab has a certain quality on the rail and rail vertical
A constant force F pull rod AB parallel to the rail is used so that it starts from rest and moves to the right
The magnetic field produced by the resistance and induced current of the rod and guide rail can not be neglected
The E is used to represent the induced electromotive force in the loop, and the I represents the induced current in the loop. When the I increases over time, the power consumed by the resistor is equal to that of the circuit
Power of A F
The absolute value of the power of B Amperes
Power of resultant force of C, F and Ampere force
D iE
12. in the vertical uniform magnetic field, the horizontal deformation of a single turn round metal coil, is prescribed direction in the coil induction current as shown in Figure 1, the magnetic induction intensity of B when the magnetic field with time t as shown in Figure 2 when changes in Figure 3 correctly represent the electromotive force in coil the change of E is
13. as shown in Figure 4, the metal wire with a long L quality regardless of slender rod and an upper arc length, arc length of the frame and suspension point connection to the O point, there is a hanging point just below the arc length is 2, the arc length of vertical paper 2 the direction of the magnetic field, and < L
First pull the wire frame to the position shown in Figure 4, then let the wire frame enter the magnetic field and ignore the air resistance and friction
The following statement is correct
When the metal wire frame enters the magnetic field, the direction of the induced current is A.
When the B. wire frame leaves the magnetic field, the direction of the induced current is
C. the metal wire frame DC edge enters the magnetic field and the AB side, leaving the magnetic field speed is always equal
The D. metal wire frame will eventually do simple harmonic motion in the magnetic field
As figure 14. shows, with a parallel level metal guide rail bulb L placed in the uniform magnetic field, a conductor rod and two guide good contact and do reciprocating motion, the motion and spring oscillator do the simple harmonic motion of the same
The position of the O in the figure corresponds to the equilibrium position of the spring oscillator, and the positions of P and Q two correspond to the maximum displacement of the spring oscillator
If the resistance of the two rail does not count,
In a A. rod from O to P, the current in the circuit becomes larger
In the B. rod from P to Q, the current in the circuit has been increasing
When the C. rod passes through the O, the direction of the current in the circuit will change
When the D. rod passes through the O, the current in the circuit is the maximum
15. long enough metal rectangular rails with L apart are shown as shown. They have one side on the same horizontal plane, and the other perpendicular to the horizontal plane
The quality of the metal rod is m, AB and CD contact with the rail vertically to form a closed loop. The dynamic friction coefficient between the rod and the guide rail is mu, the resistance of the rail is ignored, and the total resistance is 2R
The whole device is in a uniform magnetic field with a magnetic induction magnitude of B and a vertical upward direction
When the AB rod acts parallel to the horizontal rail, F moves uniformly along the rail at the speed V1, and the CD rod moves at the same rate as the velocity V2
The acceleration of gravity is g
The following statement is correct
The tensile force F of A.ab rod is mg+
The friction force on the B.cd rod is zero
The current intensity in the C. loop is
The relation between D. Mu and V1 size is mu =
16., there is a strong magnetic field between two parallel dotted lines in the drawing. The distance between the dotted lines is l, and the direction of the magnetic field is perpendicular to the surface
ABCD is a ladder coil in paper, and the distance between AD and BC is l
T = 0, the BC edge coincides with the boundary of the magnetic field (Fig.)
The coil is passed through the magnetic field at a constant speed, V, in the direction perpendicular to the boundary of the magnetic field
When the induction current is positive along a, B, C, D, a, t, the line of induced current I varies with time in the process of winding through the magnetic field
17. as shown above, a vertical bar magnet is placed above the closed coil, and the N of the magnet is extremely downward
When the magnet moves downward (but not inside the coil),
The direction of the induced current in the A. coil is the same as in the arrow in the picture. The magnet and the coil attract
each other
The direction of the induced current in the B. coil is the same as in the arrow in the figure, and the magnet and coil repel each other
The direction of the induced current in the C. coil is opposite to the arrow in the picture. The magnet and the coil attract each other
The direction of the induced current in the D. coil is opposite to the arrow in the figure, and the magnet and the coil repel each other
18. wire middle section is folded into a closed square, each side is l, which in the magnetic induction intensity is B and the direction of rotation as uniform magnetic field in the graph, the rotation speed is n, a, B two in the wire through the brush connected with the external circuit, the external circuit with rated power of P a small bulb and normal light circuit in addition to light bulbs, regardless of the rest of the resistance, resistance to bulb
(indefinite choice)
A B
C D
19. the rectangular coil ABCD in a uniform strong magnetic field rotates at the constant angular speed around the AB edge, the
direction of the magnetic field parallel to the surface of the paper and perpendicular to the ab
At the t=0 moment, the coil plane coincides with the surface of the paper (Figure), and the CD edge of the coil moves outward from the sheet
Provided that the induced current of the A, B, C, t, D, a direction is positive, the current line of the induced current in the coil I varies with time
26, book chizhe paper will work, art chizhe technology will yield -- Pu Songling