好用的
公式
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--人民币大写的函数公式21933
好用的公式--人民币大写的函数公式
人民币大写的函数公式,可正负
無條件捨去:
=CONCATENATE(IF(A1<0,"負",""),TEXT(IF(TRUNC(A1)=0,"零
",TRUNC(ABS(A1))),"[DBNum2]")&"元
",IF(OR(AND(ABS(A1)<0.1,TRUNC(A1)=A1),RIGHT(INT(ABS(A1)*100),2)="00"),"",TEXT(RIGHT(TRUNC(A1*10),1),"[DBNum2]")),IF(RIGHT(TRUNC(A1*10),1)="0","","角
"),IF(OR(TRUNC(A1*10)-(A1*10)=0,RIGHT(TRUNC(A1*100),1)="0"),"整
",TEXT(RIGHT(TRUNC(A1*100),1),"[DBNum2]")&"分"))
小數點後兩位四捨五入:
=CONCATENATE(IF(A1<0,"負",""),TEXT(IF(TRUNC(ROUND(A1,2))=0,"零
",TRUNC(ABS(ROUND(A1,2)))),"[DBNum2]")&"元
",IF(TRUNC(ROUND(A1,2))=ROUND(A1,2),"",TEXT(RIGHT(TRUNC(ROUND(A1,2)*10),1),"[DBNum2]")),IF(RIGHT(TRUNC(ROUND(A1,2)*10),1)="0","","角
"),IF(OR(TRUNC(ROUND(A1,2)*10)-(ROUND(A1,2)*10)=0,RIGHT(ROUND(A1,2),1)="0",TRUNC(ROUND(A1,2))=ROUND(A1,2)),"整",TEXT(RIGHT(ROUND(A1,2),1),"[DBNum2]")&"分"))
我再次修订:
无条件舍去:
=IF(A1<0,"负","")&SUBSTITUTE(TEXT(TRUNC(A1),"[DBNum2]")&"元
"&IF(ISNUMBER(FIND(".",TRUNC(A1,2))),TEXT(RIGHT(TRUNC(A1*10)),"[DBNum2]")&IF(ISNUMBER(FIND(".0",A1)),"","角
"),"")&IF(LEFT(RIGHT(TRUNC(A1,2),3),1)=".",TEXT(RIGHT(TRUNC(A1,2)),"[DBNum2]")&"分","整"),"-",)
小数点后两位四舍五入:
=IF(A1<0,"负","")&SUBSTITUTE(TEXT(TRUNC(ROUND(A1,2)),"[DBNum2]")&"元
"&IF(ISNUMBER(FIND(".",ROUND(A1,2))),TEXT(RIGHT(TRUNC(ROUND(A1,2)*10)),"[DBNum2]")&IF(ISNUMBER(FIND(".0",ROUND(A1,2))),"","角
"),"")&IF(LEFT(RIGHT(TRUNC(ROUND(A1,2),2),3),1)=".",TEXT(RIGHT(ROUND(A1,2)),"[DBNum2]")&"分","整"),"-",)
再簡化如後:
无条件舍去:
=IF(A1<0,"負","")&TEXT(TRUNC(ABS(A1)),"[DBNum2]")&"元
"&IF(ISERR(FIND(".",TRUNC(A1,2))),"",TEXT(RIGHT(TRUNC(A1*10)),"[DBNum2]"))&IF(RIGHT(TRUNC(A1*10))="0","","角
")&IF(LEFT(RIGHT(TRUNC(A1,2),3))=".",TEXT(RIGHT(TRUNC(A1,2)),"[DBNum2]")&"分","
整")
小数点后两位四舍五入:
=IF(A1<0,"負","")&TEXT(TRUNC(ABS(ROUND(A1,2))),"[DBNum2]")&"元
"&IF(ISERR(FIND(".",ROUND(A1,2))),"",TEXT(RIGHT(TRUNC(ROUND(A1,2)*10)),"[DBNum2]"))&IF(ISERR(FIND(".0",TEXT(A1,"0.00"))),"角
","")&IF(LEFT(RIGHT(ROUND(A1,2),3))=".",TEXT(RIGHT(ROUND(A1,2)),"[DBNum2]")&"分","整")
Function ldy888(M)
y = Int(Round(100 * Abs(M)) / 100)
j = Round(100 * Abs(M) + 0.00001) - y * 100
f = Round((j / 10 - Int(j / 10)) * 10) A = IIf(y < 1, "", Application.Text(y, "[DBNum2]") & "元")
b = IIf(j > 9.4, Application.Text(Int(j / 10), "[DBNum2]") & "角", IIf(y < 1, "", IIf(f > 0.4, "零", "")))
c = IIf(f < 1, "整", Application.Text(Round(f, 0), "[DBNum2]") & "分")
ldy888 = IIf(Abs(M) < 0.005, "", IIf(M < 0, "负" & A & b & c, A & b & c)) End Function
Public Function dx(n)
dx = Replace(Application.Text(Round(n+0.00000001, 2), "[DBnum2]"), ".", "元") dx = IIf(Left(Right(dx, 3), 1) = "元", Left(dx, Len(dx) - 1) & "角" & Right(dx, 1) & "分", IIf(Left(Right(dx, 2), 1) = "元", dx & "角整", IIf(dx = "零", "", dx & "元整")))
dx = Replace(Replace(Replace(Replace(dx, "零元零角", ""), "零元", ""), "零角", "
") 零"), "-", "负
End Function