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OLS_Estimator_Asympotic_Normality

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OLS_Estimator_Asympotic_Normality Asymptotic Normality of OLS Estimators Consider the linear regression model yt = 0zt + ut; t = 1; : : : ; T; where the parameter and the regressor zt are k-dimensional vectors. We assume that E [ut] = 0 and E [ztut] = 0k; that the moment matrices E [zt...

OLS_Estimator_Asympotic_Normality
Asymptotic Normality of OLS Estimators Consider the linear regression model yt = 0zt + ut; t = 1; : : : ; T; where the parameter and the regressor zt are k-dimensional vectors. We assume that E [ut] = 0 and E [ztut] = 0k; that the moment matrices E [ztz0t] and E [(ztz0t)u2t ] are finite, and denote �2 = E [u2t ] = V [ut] : The OLS estimator of is ^ = TX t=1 ztz 0 t !�1 TX t=1 ztyt ! = + 1 T TX t=1 ztz 0 t !�1 1 T TX t=1 ztut ! : Hence, p T ( ^ � ) = 1 T TX t=1 ztz 0 t !�1 1p T TX t=1 ztut ! : Since 1 T PT t=1 ztz 0 t converges to E [ztz0t] in probability and 1pT PT t=1 ztut converges in distribution to a multivariate normal with mean 0k and covariance matrix E [(ztz0t)u2t ], we have that p T ( ^ � ) converges in distribution to a multivariate normal with mean 0k and covariance matrix (E [ztz0t]) �1 � E [(ztz0t)u2t ] � (E [ztz0t])�1 : Note that if zt and ut are assumed to be independent, then the covariance matrix simplifies to �2 � (E [ztz0t])�1 : Let us now specialize to the case in which there is an intercept and only one pure regressor xt: Then k = 2 and zt = h 1 xt i0 : It follows that (E [ztz0t]) �1 = " 1 E [xt] E [xt] E [x2t ] #�1 = 1 V [xt] " E [x2t ] �E [xt] �E [xt] 1 # and (E [ztz0t]) �1 (ztz 0 t) (E [ztz0t]) �1 = 1V[xt]2 " E [x2t ] �E [xt] �E [xt] 1 #" 1 xt xt x 2 t #" E [x2t ] �E [xt] �E [xt] 1 # = 1V[xt]2 " E [x2t ]� E [xt] xt E [x2t ]xt � E [xt] x2t �E [xt] + xt �E [xt]xt + x2t #" E [x2t ] �E [xt] �E [xt] 1 # 1 = 1V[xt]2 " (E [x2t ]� xtE [xt])2 � (E [xt]� xt) (E [x2t ]� E [xt] xt) � (E [xt]� xt) (E [x2t ]� E [xt]xt) (xt � E [xt])2 # ; and so (E [ztz0t]) �1 � E �(ztz0t)u2t � � (E [ztz0t])�1 = 1 V [xt]2 " E h (E [x2t ]� xtE [xt])2 u2t i �E [((E [xt]� xt) (E [x2t ]� E [xt] xt))u2t ] �E [((E [xt]� xt) (E [x2t ]� E [xt] xt))u2t ] E � (xt � E [xt])2 u2t � # : Under the assumption that xt and ut are independent, we further have E h� xtE [xt]� E � x2t ��2 u2t i = E h� xtE [xt]� E � x2t ��2iE �u2t � = E �x2t � � V [xt] � �2; E �� (E [xt]� xt) � E � x2t �� E [xt]xt��u2t � = E ��(E [xt]� xt) �E �x2t �� E [xt]xt���E �u2t � = E [xt] � V [xt] � �2; E � (xt � E [xt])2 u2t � = E � (xt � E [xt])2 � E � u2t � = V [xt] � �2; and the covariance matrix �2 � (E [ztz0t])�1 simplifies to �2 V [xt] � " E [x2t ] �E [xt] �E [xt] 1 # : 2
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