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机械厂装配车间输送带传动装置设计q 课程名称: 机械设计 题目名称: 机械厂装配车间输送带传动装置设计 学 院: 徐海学院 专业班级: 机自10-5班 学 号: 22101393 姓 名: 陆明皓 目 录 机械设计任务书 机械课程设计任务书 ·······················································································...

机械厂装配车间输送带传动装置设计
q 课程名称: 机械 设计 领导形象设计圆作业设计ao工艺污水处理厂设计附属工程施工组织设计清扫机器人结构设计 快递公司问题件快递公司问题件货款处理关于圆的周长面积重点题型关于解方程组的题及答案关于南海问题 目名称: 机械厂装配车间输送带传动装置设计 学 院: 徐海学院 专业班级: 机自10-5班 学 号: 22101393 姓 名: 陆明皓 目 录 机械设计任务书 机械课程设计任务书 ························································································1 机械课程设计第一阶段 1.1、确定传动 方案 气瓶 现场处置方案 .pdf气瓶 现场处置方案 .doc见习基地管理方案.doc关于群访事件的化解方案建筑工地扬尘治理专项方案下载 ·····························································································2 1.2、电动机选择 ·······························································································3 1.3、传动件的设计 ····························································································5 机械课程设计第二阶段 2.1装配草图设计第一阶段说明·········································································17 2.2轴的设计及校核·························································································17 2.3滚动轴承的选择·························································································21 2.4键和联轴器的选择······················································································22 机械课程设计第三阶段 3.1、减速器箱体及附件的设计·········································································23 3.2、润滑方式、润滑剂及密封装置的选择·························································24 机械课程设计小结 4.1、机械课程设计小结 ·················································································25 附1:参考文献 机械课程设计任务书 一、课程设计的内容 题目D10.机械厂装配车间输送带传动装置设计 设计一带式运输机传动装置(见 图1)。图2为参考传动方案。 二、课程设计的要求与数据 1、设计条件: 1)机器功用 由输送带传送机器的零部件; 2)工作情况 单向运输、轻度振动、环境温度不超过35℃; 3)运动要求 输送带运动速度误差不超过5%; 4)使用寿命 10年,每年350天,每天16小时; 5)检修周期 一年小修;两年大修; 6)生产批量 单件小批量生产; 7)生产厂型 中型机械厂 2、设计任务 1)设计内容 1、电动机选型;2、带传动设计;3、减速器设计;4、联轴器选型设计;5、其他。 2)设计工作量 1、传动系统安装图1张;2、减速器装配图1张;3、零件图2张;4、设计计算 说明书 房屋状态说明书下载罗氏说明书下载焊机说明书下载罗氏说明书下载GGD说明书下载 一份。 3、原始数据 主动滚筒扭矩(N·m) :1400 主动滚筒速度(m/s) :0.8 主动滚筒直径(mm) :380 设计计算及说明 结  果 齿根高 f 2.5 2.5 齿顶圆直径da 58.86 235.02 齿根圆直径df 47.6 223.77 中心距a 144 齿宽b 50 43 分度圆直径 92 290 齿顶高ha 5 5 齿根高 f 4 4 齿顶圆直径da 100 298 齿根圆直径df 82 280 中心距a 192 齿宽b 80.6 73.6 二、机械课程设计第一阶段 2.1、装配草图设计第一阶段说明 1)、减速器装备图采用三个视图及必要局部剖视图才能表达完整。根据传动件尺寸大小,参考类似的减速器装配图,估计出待设计的减速器外部轮齿尺寸,并考虑标题栏、明细栏、零件序号及技术要求等位置,选择合适的比例尺,合理的布局图面。 2)、在俯视图的位置上画三根线作为传动轴1、2、3的中心线,并绘出传动件的外廓。小轮宽度应大于大齿轮5 10mm,二级传动件之间的轴向间隙 =8 15mm。 3)、画出箱体内壁线及减速器中心线。在俯视图上小齿轮端面与箱体内壁之间间隙和大齿轮顶圆之间间隙为 。 4)、按纯扭矩初步估算轴径。确定轴的跨距。先按纯扭矩确定轴径,在经轴的阶梯化吧跨距准确的确定下来。按照纯扭矩计算轴径时,用降低许用扭转剪切应力的方法来计入弯矩的影响。 2.2、轴的设计及校核 1、轴1的设计计算 1)、计算作用在齿轮上的力 圆周力Ft=2T1/d1=2×98250/53.9 径向力 轴向力 2)、初步估算轴的直径 选取45号钢材作为轴的材料,调制处理 由式8-2: ,计算轴的最小直径并加大3%以考虑键槽的影响。查表8.6 取A=115 则 =23.66 高速轴工作简图如图(a)所示 首先确定个段直径 A段: =25mm 由最小直径算出。 B段: =28mm。 C段: =30mm,与轴承(深沟球轴承6206)配合,取轴承内径 D段: =38mm, 设计非定位轴肩取轴肩高度h=4mm E段: =46mm,将高速级小齿轮设计为齿轮轴,考虑依据《课程设计指导书》p116 F段: =87mm, 设计非定位轴肩取轴肩高度h=4mm G段, =30mm, 与轴承(深沟球轴承6360)配合,取轴承内径 第二、确定各段轴的长度 A段: =55mm。 B段: =55mm,考虑轴承盖与其螺钉长度然后圆整取55mm C段: =29mm, 与轴承(深沟球轴承6206)配合,加上挡油盘长度(参考《减速器装配草图设计》p24) =B+△3+2=16+11+2=29mm D段: =98mm。 E段: ,齿轮的齿宽 F段: , =△2-2=11-2=9mm G段: =14mm, 与轴承(深沟球轴承6360)配合,加上挡油盘长度 2、轴Ⅱ的设计计算 1)、按齿轮轴设计,轴的材料取与高速级小齿轮材料相同,40Cr,调质处理,查表15-31,取 2)初算轴的最小直径 因为带轮轴上有键槽,故最小直径加大3%, =45mm。根据减速器的结构,轴Ⅱ的最小直径应该设计在与轴承配合部分,初选圆锥滚子轴承30209,故取 =45mm 轴Ⅱ的设计图见草图,由下向上同一号轴知道: 首先,确定各段的直径 A段: =45mm,与轴承(圆锥滚子轴承30209)配合, =27mm。 B段: =50mm, 非定位轴肩,与齿轮配合, =8mm。 C段: =58mm, 齿轮轴上齿轮的分度圆直径, =75mm。 D段: =50mm, 。 E段: =45mm, =43mm。 3、轴Ⅲ的设计计算 轴的材料选用40Cr(调质),可由表15-3查得 =107 所以轴的直径: EMBED Equation.3 =47.5mm。因为轴上有两个键槽,故最小直径加大6%, =50mm。 由表13.1(机械设计课程设计指导书)选联轴器型号为LH4 轴孔的直径 =50mm长度L=84mm 轴Ⅲ设计图 如下: 首先,确定各轴段直径 A段: =60mm, 与轴承(深沟球轴承6212)配合 B段: =65mm,非定位轴肩,h取5mm C段: =75mm,定位轴肩,取h=5mm D段: =65mm, 非定位轴肩,h=3.5mm E段: =60mm, 与轴承(深沟球轴承6212)配合 F段: =58mm,按照齿轮的安装尺寸确定 G段: =50mm, 联轴器的孔径 然后、确定各段轴的长度 A段: =43mm,由轴承长度,△3,△2,挡油盘尺寸 B段: =72mm,齿轮齿宽减去2mm,便于安装 C段: =10mm, 轴环宽度,取圆整值 根据轴承(深沟球轴承6212)宽度需要 D段: =86mm,由两轴承间距减去已知长度确定 E段: =29mm, 由轴承长度,△3,△2,挡油盘尺寸 F段: =57mm, 考虑轴承盖及其螺钉长度,圆整得到 G段: =84mm,联轴器孔长度。 4、轴的校核计算 第一根轴: 求轴上载荷 已知: 设该齿轮轴齿向是右 旋,受力如右图: 由材料力学知识可求得 水平支反力: 垂直支反力: EMBED Equation.3 合成弯矩 由图可知,危险截面在C右边 W=0.1 =9469 = /W=14.49MPa<70MPa 轴材料选用40Cr 查手册 符合强度条件! 第二根轴和第三根轴的具体校核步骤省略,两根轴都符合强度条件。 2.3、滚动轴承的选择 高速轴(1轴)上滚动轴承的选择 因为支撑跨距不大,故采用两端固定式轴承组合方式, 轴承类型选择深沟球轴承,轴承的预期寿命为 h。 由前计算结果所知, 轴承所受径向力 N 轴向力 N 基本额定动载荷 KN, 基本额定静载荷 KN 轴承工作转速 r/min 初选滚动轴承 6206 GB∕T276-94 (参见附录E-2) e =0.21 X=0.56 Y =2.09, 径向当量动载荷 因为 < 所以选深沟球轴承6206 GB∕T276-94 满足要求,相关数据如下: D=62 mm B=16 mm mm 低速轴的轴承校核同上,具体步骤省略,符合强度。 2.4、键联接和联轴器的选择 高速轴(1轴) 由前面的计算结果知:工作转矩T=24.42 N·m, 工作转速 r/min 选择工作情况系数 K=1.75 计算转矩 N·m 选TL型弹性套柱销联轴器。 按附录F,选用TL4联轴器, 型号为: GB4323—84 许用转矩[T]=63 N·m,许用转速[n]=5700 r/min. 因 <[T],n<[n],故该联轴器满足要求。 选A型普通平键: 初选键:b=8 mm,h=7 mm,L=34 mm,l=26 mm 参考文献[5]表4-3-18,[σ]=110MPa,[τ]=90MPa 由表4-3-16, < [σ] MPa < [τ] MPa 键的挤压强度和剪切强度都满足要求。 中间轴(2轴)上键联接的选择 由前面的计算结果知: 工作转矩T=112.33 N·m 选A型普通平键。 高速极大齿轮连接键: 初取:b=12 mm,h=8 mm,L=32 mm,l=20 mm 键 12×32 GB1096—79 参考文献[5]表4-3-18,[σ]=110 MPa,[τ]=90 MPa 由表4-3-16, < [σ] MPa < [τ] MPa 键的挤压强度和剪切强度都满足要求。 低速轴的键校核同上,具体步骤省略,符合强度。 三、机械课程设计第三阶段 3.1、减速器箱体及附件的设计 箱体有关尺寸: 箱体壁厚: 箱盖壁厚: 箱座凸缘厚度: 箱盖凸缘厚度: 箱座底凸缘厚度: 箱座上的肋厚: 箱盖上的肋厚: 地脚螺栓直径:      地脚螺栓数目: 螺栓通孔直径: 螺栓沉头座直径: 地脚凸缘尺寸: 轴承旁联接螺栓直径: 螺栓通孔直径: 螺栓沉头座直径: 剖分面凸缘尺寸: 上下箱联结螺栓直径: 螺栓通孔直径: 螺栓沉头座直径: 剖分面凸缘尺寸: 定位销直径: 轴承旁凸台半径: 大齿轮顶圆与内箱壁距离 箱体外壁至轴承座端面距离 剖分面至底面高度: 轴承盖: 1轴: 2轴: 3轴: 3.2、润滑方式、润滑剂及密封装置的选择 齿轮采用脂润滑,工业闭式齿轮油,GB 5903-95,粘度 牌号:L-CKB150,运动粘度135~165 mm/s(40℃),倾点-8 ℃,粘度指数大于90轴承采用脂润滑,通用钾基润滑脂,GB 7324-94,代号1号,滴点大于170℃,工作锥入度31~34 mm(25℃,150g)密封用毡圈密封。 四、课程设计小结 专业课课程设计当中,学到了很多东西。不仅加深了对所学知识的了解,巩固了所学知识,知道了如何很好地学以致用,把握继承与创新的结合,同时对一项设计过程如何去展开有一个大体的把握,即应该有一个大体的轮廓,采用自顶向下的设计方法,同时考虑在每一个部分、每一个过程当中与其他部分、过程的相互联系。感觉最繁琐的莫过于忽视了某个因素,导致了该部件设计必须重新开始,降低了设计速度,这应该在以后的设计过程当中应当尽量避免。同时要加深对专业知识的学习,对某些知识还是不是很清楚,只能简简单单套套公式进行计算或是计算不熟练,往往忽略某一因素而导致重新计算,突出的地方就是轴上力 分析 定性数据统计分析pdf销售业绩分析模板建筑结构震害分析销售进度分析表京东商城竞争战略分析 的时候,要么忽略力或由力产生的力矩,要么方向弄错,总之,第一根轴力分析还有轴承校核的时候计算了三四遍,在这以后要相当注意,要加强力学与工程应用这方面的学习。 通过本次课程设计,不仅对以往所学的知识的理解有了提高,还对一些必要软件的使用有了一定的了解,尤其是AutoCAD2010的使用,和Word 2007的排版和使用都有很大的提高。 还有一点就是设计是一门需要通过长期准备的工作,刚开始是就匆匆下手,到后来才发现有许多的不合适之处,需要把以前的结果重新计算,有一种欲速则不达感觉。通过本次课程设计,我明白了不论做任何设计都不是一蹴而就的,需要一步一步的完成,一个一个细节部件的去完成同时还要考虑各个部件之间的联系,之后再检查、完善、修改,最后整理思路,在回顾设计,查缺补漏,最后完成整个设计。 机械课程设计是一门相当综合的学科,它几乎包含了我们所学的所有专业基础课程,如《机械原理》、《机械设计》、《理论力学》、《材料力学》、《几何公差与检测》、《画法几何及机械制图》等等。进行课程设计,对以往所学内容的掌握情况也是一种考验,对不熟悉的内容进行巩固和学习。 参考文献 程志红 唐大放主编 机械设计课程上机与设计 东南大学出版社 2006 程志红主编 机械设计 东南大学出版社 2006 王洪欣 冯雪君主编 机械原理 东南大学出版社 2007 甘永立主编 几何量公差与检测 上海科学技术出版社 2010 李爱军 陈国平主编 画法几何及机械制图 中国矿业大学出版社 2007 【6】 吴宗泽主编 机械设计手册 机械工业出版社 2002 =40.22 =0.82 =7.2kW P=7.9KW 36.30 4.86 3.74 n1=730r/min n2=150.21r/min n3=40.16r/min P1=7.51KW P2=7.21KW P3=6.92KW T1=98.25 T2=458.39 T3=1645.58 KA=1.2 Pc=9.48 kw A 型 D1=100 mm D2=200 mm V=7.64 m/s 带速符合要求 Ld=1800 mm a=662 mm =171.3°>120° P0=1.32 ⊿P0 =0.17 Ka=0.98 KL=1.01 Z=5 F0=141.45 Q=1410.43 N1=2.45×109 N2=5.04×108 2公差组8级 z1=21 合格 m=2.5m v=2.06m/s b=45mm b2=45mm N1=5.05×108 N1=1.35×108 2公差组8级 u=3.74 合格 m=4 v=0.723m/s b=73.6mm EMBED Equation.DSMT4 Ft=3645.64N Fr=1361.15N Fa=311.23N =25mm =25mm =28mm =30mm =38mm =46mm =54mm =30mm =38mm =55mm =55mm =29mm =29mm =98mm =45mm =45mm =41mm =50mm =8mm =58mm =75mm =50mm =60mm =65mm =75mm =75mm =65mm =60mm =58mm =50mm =43mm =78mm =10mm =62mm =29mm =57mm =84mm =14.49MPa 6206 GB∕T276-94 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 EMBED Equation.3 机械课程设计说明书 图1 带式运输机传动装置 图2 参考传动方案 _1234568145.unknown _1234568273.unknown _1234568337.unknown _1234568369.unknown _1234568401.unknown _1234568417.unknown _1234568425.unknown _1234568429.unknown _1234568433.unknown _1234568437.unknown _1234568439.unknown _1234568440.unknown _1234568441.unknown _1234568438.unknown _1234568435.unknown _1234568436.unknown _1234568434.unknown _1234568431.unknown _1234568432.unknown _1234568430.unknown _1234568427.unknown _1234568428.unknown _1234568426.unknown _1234568421.unknown _1234568423.unknown _1234568424.unknown _1234568422.unknown _1234568419.unknown _1234568420.unknown 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