20
Analog Applications JournalAnalog and Mixed-Signal Products November 1999
Texas Instruments IncorporatedAmplifiers: Op Amps
Single-supply op amp design
Introduction
Most portable systems have one battery, thus the popularity
of portable equipment results in increased single-supply
applications. Split- or dual-supply op amp circuit design is
straightforward because op amp inputs and outputs are
referenced to the normally grounded center tap of the
supplies. In the majority of split-supply applications, sig-
nal sources driving the op amp inputs are referenced to
ground; thus with one input of the op amp referenced to
ground, as shown in Figure 1, common-mode voltage and
voltage bias problems are negligible.
When signal sources are referenced to ground, single-
supply op amp circuits exhibit a large input common-mode
voltage (Figure 2). The input voltage is not referenced to
the midpoint of the supplies like it would be in a split-
supply application; rather, it is referenced to the lower-
power supply rail. This circuit malfunctions when the
input voltage is positive because the output voltage should
go negative; this is hard to do with a positive supply. It
operates marginally with small negative input voltages
because most op amps cannot function when the inputs
are connected to the supply rails.
The constant requirement to account for input refer-
ences makes it difficult to design single-supply op amp
By Ron Mancini
Senior Application Specialist, Operational Amplifiers
PARAMETER NAME PARAMETER SYMBOL VALUE
Input current IIN 0
Input offset-voltage VOS 0
Input impedance ZIN ¥
Output impedance ZOUT 0
Gain a ¥
Table 1. Ideal op amp parameter values
+ V
- V
RG RF
VOUT
+
-
VIN
Figure 1. Split-supply op amp circuit
+ VRG RF
VOUT
VIN
-
+
Figure 2. Single-supply op amp circuit
Boundary conditions
Use of a single-supply limits the output voltage range to the
positive supply voltage. This limitation precludes negative
output voltages when the circuit has a positive supply volt-
age, but it does not preclude negative input voltages. As
long as the voltage on the op amp input leads does not
become negative, the circuit can handle negative input
voltages.
Beware of working with negative input voltages when
the op amp is powered from a positive supply because op
amp inputs are highly susceptible to reverse voltage break-
down. Also, insure that all possible startup conditions do
not reverse bias the op amp inputs when the input and
supply voltage are of opposite polarity.
Simultaneous equations
Taking an orderly path to developing a circuit that works
the first time means following these steps until the equa-
tion of the op amp is determined. Use specifications and
simultaneous equations to determine what form the op amp
equation must have. Go to the section that illustrates that
equation form (called a case), solve the equations to deter-
mine the resistor values, and you have a working solution.
A linear op amp transfer function is limited to the equa-
tion of a straight line.
(1)
The equation of a straight line has four possible solu-
tions depending upon the sign of m (the slope) and b
(the intercept), thus simultaneous equations yield solu-
tions in four forms. Four circuits are developed, one for
each form of the equation of a straight line. The four
equations, cases, or forms of a straight line are given in
Equations 2 through 5 where electronic terminology has
been substituted for math terminology.
bmxy ––=
circuits. This application note develops an orderly procedure
for designing single-supply op amp circuits that leads to a
working design every time. Application Note SLAA068,
entitled, “Understanding Basic Analog—Ideal Op Amps,”
develops the ideal op amp equations. The ideal op amp
assumptions used to write ideal op amp equations are
shown in Table 1 for your reference.
www.ti.com/sc/docs/products/analog/tlc070.html
Texas Instruments Incorporated Amplifiers: Op Amps
21
Analog Applications Journal November 1999 Analog and Mixed-Signal Products
(2)
(3)
(4)
(5)
Given a set of two data points for VOUT and VIN, simulta-
neous equations are solved to determine m and b for the
equation that satisfies the given data. The sign of m and b
determines the type of circuit required to implement the
solution.
The given data is derived from the specifications; i.e., a
sensor output signal ranging from 0.1 volts to 0.2 volts must
be interfaced into an analog-to-digital converter that has
an input voltage range of 1 volt to 4 volts. These data points
(VOUT = 1.0 V @ VIN = 0.1 V, VOUT = 4.0 V @ VIN = 0.2 V) are
inserted into Equation 2, as shown in Equations 6 and 7,
to obtain m and b for the specifications.
(6)
(7)
Solving Equations 6 and 7 yields b = –2 and m = 30.
Now m and b are substituted back into Equation 2, yield-
ing Equation 8.
(8)
Notice that, although Equation 2 was the starting point,
the form of Equation 8 is identical to Equation 3. The
specifications or given data determine the sign of m and
b, and starting with Equation 2, the final equation form is
discovered after m and b are calculated. The next step is
to develop a circuit that has an m = 30 and b = –2 to com-
plete the problem solution. Circuits were developed for
Equations 2 through 5, and they are given under the
headings Case 1 through Case 4, respectively.
Case 1 — VOUT = mVIN + b
The circuit configuration that yields a solution for Case 1
is shown in Figure 3.
2V30V INOUT -=
bm += )2.0(4
bm += )1.0(1
bm --= INOUT VV
bm +-= INOUT VV
bm -= INOUT VV
bm += INOUT VV
The circuit equation is written using the voltage divider
rule and superposition.
(9)
(10)
(11)
Case 2 — VOUT = mVIN – b
The circuit shown in Figure 4 yields a solution for Case 2.
The circuit equation is obtained by taking the Thevenin
equivalent circuit looking into the junction of R1 and R2.
After the R1, R2 circuit is replaced with the Thevenin
equivalent circuit, the gain is calculated with the ideal
gain equation.
(12)
(13)
(14)
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INOUT
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R
V
R
RR
RR
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VV
+ V
RG RF
VOUT
VIN
R1
R2VREF
TLV2471
+
-
Figure 3. Schematic for Case 1 —
VOUT = mVIN + b
+ V
RG RF
VOUT
VINVREF
R2
R1
TLV2471
+
-
Figure 4. Schematic for Case 2 —
VOUT = mVIN – b
Continued on next page
www.ti.com/sc/docs/products/analog/tlc080.html www.ti.com/sc/docs/products/analog/tlv2470.html
Texas Instruments IncorporatedAmplifiers: Op Amps
22
Analog Applications JournalAnalog and Mixed-Signal Products November 1999
Case 3 — VOUT = –mVIN + b
The circuit shown in Figure 5 yields the transfer function
desired for Case 3.
The circuit equation is obtained with superposition.
(15)
(16)
(17)
Case 4 — VOUT = –mVIN – b
The circuit shown in Figure 6 yields a solution for Case 4.
The circuit equation is obtained by using superposition to
calculate the response to each input. The individual
responses to VIN and VREF are added to obtain Equation 18.
(18)
(19)
(20)
Conclusion
Single-supply op amp design is more complicated than
split-supply op amp design, but with a logical design
approach excellent results are achieved. Single-supply
design was considered technically limiting because the
older op amps had limited capability. Op amps such as
the TI TLV247x, TLC07x, and TLC08x have excellent
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INOUT R
RR
RR
R
V
R
R
VV
VREF
+ V
RG RF
VOUT
VIN
R1
R2 TLV2471
+
-
Figure 5. Schematic for Case 3 —
VOUT = –mVIN + b
+ V
RG1 RF
VOUT
VIN
VREF
RG2
TLV2471
+
-
Figure 6. Schematic for Case 4 —
VOUT = –mVIN – b
Continued from previous page
single-supply parameters; thus, when used in the correct
applications, these op amps yield rail-to-rail performance
far surpassing their split-supply counterparts. More in-
depth information concerning single-supply op amp
design can be found in Texas Instruments Application
Note SLOA030, entitled, “Single-Supply Op Amp Design
Techniques.”
www.ti.com/sc/docs/products/analog/tlc070.html
www.ti.com/sc/docs/products/analog/tlc080.html
www.ti.com/sc/docs/products/analog/tlv2470.html
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